Używam Rinjael do kodowania w VB.NET i potrzebuję dekodować w Ruby. Moja klasa szyfrowania VB.NET wygląda tak:

Private Class Encryptor
        Private symmetricKey As System.Security.Cryptography.RijndaelManaged
        Private iVector As Byte()
        Private Key As Byte()
        Public Function encrypt(ByVal data As String) As String
            Try
                Dim plainTextBytes As Byte() = System.Text.Encoding.ASCII.GetBytes(data)
                Dim encryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateEncryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, encryptor, System.Security.Cryptography.CryptoStreamMode.Write)
                cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length)
                cryptoStream.FlushFinalBlock()
                Dim cipherTextBytes As Byte() = memoryStream.ToArray()
                memoryStream.Close()
                cryptoStream.Close()
                Return Convert.ToBase64String(cipherTextBytes)
            Catch
                Return ""
            End Try
        End Function
        Public Function decrypt(ByVal data As String) As String
            Try
                Dim crypted As Byte() = Convert.FromBase64String(data)
                Dim decryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateDecryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream(crypted)
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, decryptor, System.Security.Cryptography.CryptoStreamMode.Read)
                Dim plain(crypted.Length) As Byte
                Dim count As Integer = cryptoStream.Read(plain, 0, plain.Length)
                memoryStream.Close()
                cryptoStream.Close()
                Return System.Text.Encoding.UTF8.GetString(plain, 0, count)
            Catch
                Return ""
            End Try
        End Function

        Public Sub New(ByVal clientkey As String)
            iVector = System.Text.Encoding.ASCII.GetBytes("1234567890123456")
            Key = System.Text.Encoding.ASCII.GetBytes(clientkey)
            symmetricKey = New System.Security.Cryptography.RijndaelManaged
            symmetricKey.Mode = System.Security.Cryptography.CipherMode.CBC
        End Sub
    End Class

to działa dobrze i jestem w stanie odszyfrować w java przy użyciu AES / CBC / PKCS5Padding. Teraz moje hasło i iv mają 16 znaków (16 * 16 bitów = 256). Kiedy próbuję odszyfrować w Ruby, narzeka, że ​​moje hasło jest krótkie ... Zakładam, że używa znaków 8-bitowych. Używam tej klasy do deszyfrowania w rubinie:

    require 'openssl'

module Crypt
  # Decrypts a block of data (encrypted_data) given an encryption key
  # and an initialization vector (iv).  Keys, iv's, and the data 
  # returned are all binary strings.  Cipher_type should be
  # "AES-256-CBC", "AES-256-ECB", or any of the cipher types
  # supported by OpenSSL.  Pass nil for the iv if the encryption type
  # doesn't use iv's (like ECB).
  #:return: => String
  #:arg: encrypted_data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String
  def Crypt.decrypt(encrypted_data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.decrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(encrypted_data) + aes.final  
  end

  # Encrypts a block of data given an encryption key and an 
  # initialization vector (iv).  Keys, iv's, and the data returned 
  # are all binary strings.  Cipher_type should be "AES-256-CBC",
  # "AES-256-ECB", or any of the cipher types supported by OpenSSL.  
  # Pass nil for the iv if the encryption type doesn't use iv's (like
  # ECB).
  #:return: => String
  #:arg: data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String  
  def Crypt.encrypt(data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.encrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(data) + aes.final      
  end
end

Teraz. Próbując odszyfrować za pomocą Crypt.decrypt (dane, klucz, iv, „AES-CBC-256”), jestem pewien, że wstępne przekształcenia ciągów / bajtów muszą być wykonane na moich danych, klucz, iv, aby działać poprawnie.

Jak zadzwonić do Crypt.decrypt za pomocą key = „passwordpassword” i iv = „1234567890123456”? Czy muszę dekodować moje dane base64?

Oto moje wywołanie deszyfrowania, które wydaje się nie działać (próba dopełnienia zerami):

   text = Base64.decode64(text)
   pass = Digest::SHA1.hexdigest("#{@pass}0000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   iv = Digest::SHA1.hexdigest("12345678901234560000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   return Crypt.decrypt(text,pass,iv,"AES-256-CBC")