Używanie XSLT do wyświetlania wielu plików

Question

Jul 13, 2009, 11:09 PM

Używanie XSLT do wyświetlania wielu plików

Próbuję uzyskać przykład, w którym znalazłem użycie XSLT 2.0 do pracy z wieloma plikami.

Używam Saxon B 9.7.0.1 z Java 1.6, otrzymuję ten błąd:

C:\Documents and Settings\Administrator\Desktop\saxon>java -jar saxon9.jar -s:input.xml -xsl:transform.xml
Error on line 15 of transform.xml:
  java.net.URISyntaxException: Illegal character in path at index 20: file:///C:/Documents
  and Settings/Administrator/Desktop/saxon/output1/test1.html
  at xsl:for-each (file:/C:/Documents%20and%20Settings/Administrator/Desktop/saxon/transform.xml#10)
     processing /tests/testrun[1]
Transformation failed: Run-time errors were reported

input.xml

<?xml version="1.0" encoding="UTF-8"?>
<tests>
    <testrun run="test1">
        <test name="foo" pass="true" />
        <test name="bar" pass="true" />
        <test name="baz" pass="true" />
    </testrun>
    <testrun run="test2">
        <test name="foo" pass="true" />
        <test name="bar" pass="false" />
        <test name="baz" pass="false" />
    </testrun>
    <testrun run="test3">
        <test name="foo" pass="false" />
        <test name="bar" pass="true" />
        <test name="baz" pass="false" />
    </testrun>
</tests>

transform.xml

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
  version="2.0">

  <xsl:output method="text"/>
  <xsl:output method="html" indent="yes" name="html"/>

  <xsl:template match="/">
    <xsl:for-each select="//testrun">
      <xsl:variable name="filename"
        select="concat('output1/',@run,'.html')" />
      <xsl:value-of select="$filename" />  <!-- Creating  -->
      <xsl:result-document href="{$filename}" format="html">
        <html><body>
          <xsl:value-of select="@run"/>
        </body></html>
      </xsl:result-document>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>