Django Admin Media pref, ix URL issue

Question

Mar 01, 2011, 09:29 AM

Django Admin Media pref, ix URL issue

Eu tenho a seguinte estrutura de pastas

src\BAT\templates\admin\base.html
src\BAT\media\base.css
src\BAT\media\admin-media\base.css

settings.py

MEDIA_ROOT = os.path.join( APP_DIR, 'media' )
MEDIA_URL = '/media/'
ADMIN_MEDIA_PREFIX = '/admin-media/'
TEMPLATE_DIRS = (
    os.path.join( APP_DIR, 'templates' )
)
INSTALLED_APPS = (
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.sites',
    'django.contrib.messages',
    'django.contrib.admin',
    'django.contrib.admindocs',
)

urls.py

urlpatterns = patterns('',
    (r'^admin/doc/', include('django.contrib.admindocs.urls')),

    (r'^admin/', include(admin.site.urls)),

    (r'^media/(?P<path>.*)Eu preciso obter os dois arquivos CSS no meu aplicativo. minha base.html contém
<head>
<title>{% block title %}{% endblock %}</title>
<link href="{{ MEDIA_URL }}css/base.css" rel="stylesheet" type="text/css" />
<link href="{{ MEDIA_URL }}{{ADMIN_MEDIA_PREFIX}}css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="{% block stylesheet %}{% load adminmedia %}{% admin_media_prefix %}css/base.css{% endblock %}" />
{% block extrastyle %}{% endblock %}
<!--[if lte IE 7]><link rel="stylesheet" type="text/css" href="{% block stylesheet_ie %}{% load adminmedia %}{% admin_media_prefix %}css/ie.css{% endblock %}" /><![endif]-->
{% if LANGUAGE_BIDI %}<link rel="stylesheet" type="text/css" href="{% block stylesheet_rtl %}{% admin_media_prefix %}css/rtl.css{% endblock %}" />{% endif %}
<script type="text/javascript">window.__admin_media_prefix__ = "{% filter escapejs %}{% admin_media_prefix %}{% endfilter %}";</script>
{% block extrahead %}{% endblock %}
{% block blockbots %}<meta name="robots" content="NONE,NOARCHIVE" />{% endblock %}
</head>
Quero obter a seguinte saída para URLhttp://localhost:8000/admin
<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/admin-media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/base.css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/dashboard.css" />
Mas eu sempre consegui
<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/base.css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/dashboard.css" />
enquanto acessa diretamentehttp://localhost:8000/admin-media/css/base.css mostra o arquivo css dos pacotes de sites Python / django / contrib / admin / media / css
enquanto acessa diretamentehttp://localhost:8000/media/admin-media/css/base.css mostra o arquivo css em src / media / admin-media / css /
enquanto acessa diretamentehttp://localhost:8000/media/css/base.css mostra o arquivo css em src / media / css /, 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}),

)

Eu preciso obter os dois arquivos CSS no meu aplicativo. minha base.html contém

<head>
<title>{% block title %}{% endblock %}</title>
<link href="{{ MEDIA_URL }}css/base.css" rel="stylesheet" type="text/css" />
<link href="{{ MEDIA_URL }}{{ADMIN_MEDIA_PREFIX}}css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="{% block stylesheet %}{% load adminmedia %}{% admin_media_prefix %}css/base.css{% endblock %}" />
{% block extrastyle %}{% endblock %}
<!--[if lte IE 7]><link rel="stylesheet" type="text/css" href="{% block stylesheet_ie %}{% load adminmedia %}{% admin_media_prefix %}css/ie.css{% endblock %}" /><![endif]-->
{% if LANGUAGE_BIDI %}<link rel="stylesheet" type="text/css" href="{% block stylesheet_rtl %}{% admin_media_prefix %}css/rtl.css{% endblock %}" />{% endif %}
<script type="text/javascript">window.__admin_media_prefix__ = "{% filter escapejs %}{% admin_media_prefix %}{% endfilter %}";</script>
{% block extrahead %}{% endblock %}
{% block blockbots %}<meta name="robots" content="NONE,NOARCHIVE" />{% endblock %}
</head>

Quero obter a seguinte saída para URLhttp://localhost:8000/admin

<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/admin-media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/base.css" />
<link rel="stylesheet" type="text/css" href="/media/admin/css/dashboard.css" />

Mas eu sempre consegui

<head>
<title>Site administration | My site admin</title>
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link href="/media/css/base.css" rel="stylesheet" type="text/css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/base.css" />
<link rel="stylesheet" type="text/css" href="/admin-media/css/dashboard.css" />

enquanto acessa diretamentehttp://localhost:8000/admin-media/css/base.css mostra o arquivo css dos pacotes de sites Python / django / contrib / admin / media / css

enquanto acessa diretamentehttp://localhost:8000/media/admin-media/css/base.css mostra o arquivo css em src / media / admin-media / css /

enquanto acessa diretamentehttp://localhost:8000/media/css/base.css mostra o arquivo css em src / media / css /