Eu sei que isso é uma duplicata e vocês vão me repreender por isso, mas eu não consegui uma solução adequada depois de ler todos os posts.
Eu estou tentando construir um aplicativo Spring Template no Spring Source Tool Suite. Eu estou recebendo o seguinte erro.

org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: A linha 16 no documento XML do recurso ServletContext [/WEB-INF/spring/appServlet/servlet-context.xml] é inválida; A exceção aninhada é org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: O curinga correspondente é estrito, mas nenhuma declaração pode ser encontrada para o elemento 'resources'.

Meu root-context.xml é assim:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:cache="http://www.springframework.org/schema/cache"
    xmlns:ehcache="http://www.springmodules.org/schema/ehcache"
    xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache-3.1.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd
        http://www.springmodules.org/schema/ehcache http://www.springmodules.org/schema/cache/springmodules-ehcache.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.0.xsd">

    <!-- Root Context: defines shared resources visible to all other web components -->

</beans>

Por favor, deixe-me saber se há um arquivo jar faltando no meu aplicativo.
Esses são os únicos arquivos jar que tenho em meu aplicativo:
displaytag-1.0-b3.jar, spring-2.0.6.jar, spring-asm-3.0.3.RELEASE.jar, spring-beans 3.0.3.RELEASE.jar, spring-context-3.0.3.RELEASE. jar, spring-core-3.0.3.RELEASE.jar, spring-expressão-3.0.3.RELEASE.jar, spring-hibernate3-2.0.8.jar, spring-web-3.0.3.RELEASE.jar & spring- webmvc-3.0.3.RELEASE.jar

Aqui está o meu servlet-context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:beans="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
        http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd">

    <!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->

    <!-- Enables the Spring MVC @Controller programming model -->
    <annotation-driven />

    <!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
    <resources mapping="/resources/**" location="/resources/" />

    <!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
    <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <beans:property name="prefix" value="/WEB-INF/views/" />
        <beans:property name="suffix" value=".jsp" />
    </beans:bean>

    <context:component-scan base-package="com.foo.controller" />



</beans:beans>

Por favor, ajude ... é muito chato.