El control ActiveX '8856f961-340a-11d0-a96b-00c04fd705a2' no se puede instanciar porque el subproceso actual no está en un apartamento de un solo subproceso

Recibo este error cuando intento mostrar un formulario con un navegador web en él.

El control ActiveX '8856f961-340a-11d0-a96b-00c04fd705a2' no se puede instanciar porque el subproceso actual no está en un apartamento de un solo subproceso

Lo llamo por:

Public Class frmMain
  Class Server
       Public Shared Sub Main()
        Dim aTcpMessaging As IMessagingSystemFactory = New TcpMessagingSystemFactory()
        Dim anInputChannel As IInputChannel = aTcpMessaging.CreateInputChannel(theIPforLocal & ":" & thePort)
        Dim aStringMessagesFactory As IStringMessagesFactory = New StringMessagesFactory()
        Dim aStringMessageReceiver As IStringMessageReceiver = aStringMessagesFactory.CreateStringMessageReceiver()
        AddHandler aStringMessageReceiver.MessageReceived, AddressOf StringMessageReceived

        aStringMessageReceiver.AttachInputChannel(anInputChannel)
    End Sub

       Private Shared Sub StringMessageReceived()
            Call New frmMM().Show()
       End Sub
  End Class

  Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
    Dim RelState As Integer = 0
    Call frmMain.Server.Main()
    lblVer.Text = "V.7"
    Pid = 0
  End Sub
End Class

¿Cómo puedo cargar esto para que no me muestre ese error?

Gracias

David

Code update

 Class Server
    <STAThread()> Public Sub Main()
        Dim aTcpMessaging As IMessagingSystemFactory = New TcpMessagingSystemFactory()
        Dim anInputChannel As IInputChannel = aTcpMessaging.CreateInputChannel(theIPforLocal & ":" & thePort)
        Dim aStringMessagesFactory As IStringMessagesFactory = New StringMessagesFactory()
        Dim aStringMessageReceiver As IStringMessageReceiver = aStringMessagesFactory.CreateStringMessageReceiver()
        AddHandler aStringMessageReceiver.MessageReceived, AddressOf StringMessageReceived

        aStringMessageReceiver.AttachInputChannel(anInputChannel)
    End Sub

   Private Shared Sub StringMessageReceived()
        Call New frmMM().Show()
   End Sub
 End Class

  Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
    Dim RelState As Integer = 0
    Call frmMain.Server.Main()   '<-- the error now
    lblVer.Text = "V.7"
    Pid = 0
  End Sub
End Class

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