Creo este código para agregar algunos datos en mi db sin repetición.
pero eso no es un trabajo y no puedo agregar datos creados por este php a mi tabla.
Cuál es el problema ?
P.S: ¡No tengo error!
P.P.S: hago esto en un servidor wamp.

<?php

    $con=mysqli_connect("localhost","root","","kosar");
    // Check connection
    if (mysqli_connect_errno()) {
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    for ($i=0;$i<10;$i++) {
        $n1 = rand(100000,999999);
        $n2 = rand(100000,999999);

        $pincode = (string)$n1;
        echo $pincode;
        echo nl2br("$pincode\n");


        mysql_query ("INSERT IGNORE INTO kosar(ID, Code, Type, Used) VALUES('', '".$pincode."','1', '0')");
        if(mysql_affected_rows() == 0)
        {
            // Duplicates found
        }else{
            // No duplicates were found
        }
    }
    for ($i=0;$i<10;$i++) {
        $n1 = rand(100000,999999);
        $n2 = rand(100000,999999);

        $pincode = (string)$n1; 
        echo $pincode;  
        echo nl2br("$pincode\n");
        mysql_query("INSERT IGNORE INTO kosar(ID, Code, Type, Used) VALUES('', '".$pincode."','2', '0')");
        if(mysql_affected_rows() == 0)
        {
            // Duplicates found
        }else{
            // No duplicates were found
        }
    }
    for ($i=0;$i<10;$i++) {
        $n1 = rand(100000,999999);
        $n2 = rand(100000,999999);

        $pincode = (string)$n1;
        echo $pincode;
        echo nl2br("$pincode\n");
        mysql_query("INSERT IGNORE INTO kosar(ID, Code, Type, Used) VALUES('', '".$pincode."','3', '0')");
        if(mysql_affected_rows() == 0)
        {
            // Duplicates found
        }else{
            // No duplicates were found
        }
    }

    mysqli_close($con);
?>