Ich möchte einen Verweis auf eine Fremdtabelle erstellen. aber ich erhalte den folgenden Fehler:

Abfrage:

CREATE TABLE category_ids (id INT, post_id INT,
                    INDEX par_ind (post_id),
                    FOREIGN KEY (post_id) REFERENCES post(id)
                      ON DELETE CASCADE
) ENGINE=INNODB;

SHOW ENGINE INNODB STATUS \ G:

------------------------
LATEST FOREIGN KEY ERROR
------------------------
2013-08-23 00:11:06 7f6f49e7b700 Error in foreign key constraint of table fun/category_ids:
FOREIGN KEY (post_id) REFERENCES post(id)
                      ON DELETE CASCADE
) ENGINE=INNODB:
Cannot resolve table name close to:
(id)
                      ON DELETE CASCADE
) ENGINE=INNODB

Beiträge Tabellenstruktur

    mysql> describe post;
    +-------------+-----------------------+------+-----+---------------------+----------------+
    | Field       | Type                  | Null | Key | Default             | Extra          |
    +-------------+-----------------------+------+-----+---------------------+----------------+
    | id          | int(11)               | NO   | PRI | NULL                | auto_increment |
...
    +-------------+-----------------------+------+-----+---------------------+----------------+
    22 rows in set (0.00 sec)