Hier ist mein Java-Code, der für die Deserialisierung verwendet wird. Ich versuche, einen JSON-String in ein Java-Objekt zu konvertieren. Dabei habe ich den folgenden Code verwendet:

package ex1jackson;
import com.fasterxml.jackson.core.JsonGenerationException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class Ex1jackson {
public static void main(String[] args) {
   ObjectMapper mapper = new ObjectMapper();
try {
        String userDataJSON = "[{\"id\":\"value11\",\"name\": \"value12\",\"qty\":\"value13\"},"
                              + "{\"id\": \"value21\",\"name\":\"value22\",\"qty\": \"value23\"}]";
        product userFromJSON = mapper.readValue(userDataJSON, product.class);
        System.out.println(userFromJSON);
    } catch (JsonGenerationException e) {
        System.out.println(e);
        } catch (JsonMappingException e) {
       System.out.println(e);
    } catch (IOException e) {
    System.out.println(e);
    } 
}
}

und meine product.java Klasse

package ex1jackson;
public class product 
{
private String id;
private String name; 
private String qty; 

@Override
public String toString() {
    return "Product [id=" + id+ ", name= " + name+",qty="+qty+"]";
}
}

Ich erhalte den folgenden Fehler.

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: 
Unrecognized field "id" (class ex1jackson.product), not marked as ignorable (0 known properties: ]) at 
[Source: java.io.StringReader@16f76a8; line: 1, column: 8] (through reference chain: ex1jackson.product["id"]) 
BUILD SUCCESSFUL (total time: 0 seconds)

hilf mir das zu lösen,