Я использую Spring 4.1.4.RELEASE + Hibernate 4.3.6.Final, вот мой код сущности:

public class BaseEntity implements Serializable {
}


public class MarketInfo extends BaseEntity {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "id")
    private int id;

    @Column(name = "market_id", unique = true, length = 15)
    private String marketId;

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "market")
    private List<MarketChannelGroup> channelGroups;

    public List<MarketChannelGroup> getChannelGroups() {
        return channelGroups;
    }

    public void setChannelGroups(List<MarketChannelGroup> channelGroups) {
        this.channelGroups = channelGroups;
    }

...
}

public class MarketChannelGroup extends BaseEntity {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "id")
    private int id;


    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "market_id", referencedColumnName = "market_id")
    private MarketInfo market;
...
}

Из моего теста я вижу, что channelGroups в MarketInfo работает нормально (если я не вызываю getChannelGroups (), тогда channelGroups имеет значение null), однако, если я вызываю getChannelGroups (), MarketInfo внутри каждой MarketChannelGroup извлекается, а это не должно случается, так как режим выборки рынка - FetchType.LAZY.

Из консоли я вижу следующий журнал гибернации, когда вызываю его геттер:

Hibernate: select channelgro0_.market_id as market_i5_12_1_, channelgro0_.id as id1_9_1_, channelgro0_.id as id1_9_0_, channelgro0_.channel_group_id as channel_2_9_0_, channelgro0_.channel_group_name as channel_3_9_0_, channelgro0_.channel_group_type as channel_4_9_0_, channelgro0_.market_id as market_i5_9_0_ from market_channel_group channelgro0_ where channelgro0_.market_id=?
Hibernate: select marketinfo0_.id as id1_12_0_, marketinfo0_.enable_flag as enable_f2_12_0_, marketinfo0_.enable_time as enable_t3_12_0_, marketinfo0_.market_id as market_i4_12_0_, marketinfo0_.market_name as market_n5_12_0_, marketinfo0_.stb_count as stb_coun6_12_0_ from market_info marketinfo0_ where marketinfo0_.market_id=?
Hibernate: select marketinfo0_.id as id1_12_0_, marketinfo0_.enable_flag as enable_f2_12_0_, marketinfo0_.enable_time as enable_t3_12_0_, marketinfo0_.market_id as market_i4_12_0_, marketinfo0_.market_name as market_n5_12_0_, marketinfo0_.stb_count as stb_coun6_12_0_ from market_info marketinfo0_ where marketinfo0_.market_id=?
Hibernate: select marketinfo0_.id as id1_12_0_, marketinfo0_.enable_flag as enable_f2_12_0_, marketinfo0_.enable_time as enable_t3_12_0_, marketinfo0_.market_id as market_i4_12_0_, marketinfo0_.market_name as market_n5_12_0_, marketinfo0_.stb_count as stb_coun6_12_0_ from market_info marketinfo0_ where marketinfo0_.market_id=?

кто-нибудь может помочь?

ОБНОВИТЬ

для аннотации ManyToOne необязательный метод, поэтому решение в OneToOne не подходит для моего случая.