Exibir cada valor do campo DISTINCT apenas uma vez usando o loop

Question

Oct 05, 2011, 11:43 PM

Exibir cada valor do campo DISTINCT apenas uma vez usando o loop

SELECT listTitle, listLength, listCmt, listDt, mBCFName, mBCLName, moAmt, moDtOff
FROM User U, Listing L, Merchant M, MerchantOffer MO
WHERE U.uID = L.uID
and L.listID = MO.listID
and M.mID = MO.mId
ORDER BY listDt DESC;

Este loop foreach ()

    $result = $sth->fetchAll(PDO::FETCH_ASSOC);
    foreach($result as $row) 
    { 
    echo "<div class='listing'>";
        print '<br>Title: ' . $row['listTitle'] . '<br>Comment: ' . $row['listCmt'] . 
        '<br>Date: ' . $row['listDt'] . '<br>Offer By: ' . $row['mBCFName']. ' ' .$row['mBCLName']. '<br> for: ' . $row['moAmt'];
    echo "</div>";
    }

produces:

Basicamente o que eu quero é:

Title: Apple iPhone 4S (listTitle)
Days: <some day amount <listLength>
Comment: some comment <listCmt>

    Offer By: some user <mBCFName mBCLName>
    Offer:  19.99 <moAmt>
    Date: 10/03/2011 < moDtOff>

    Offer By: some user <mBCFName mBCLName>
    Offer:  19.99 <moAmt>
    Date: 10/03/2011 < moDtOff>

    Offer By: some user <mBCFName mBCLName>
    Offer:  19.99 <moAmt>
    Date: 10/03/2011 < moDtOff>

    Offer By: some user <mBCFName mBCLName>
    Offer:  19.99 <moAmt>
    Date: 10/03/2011 < moDtOff>