recebendo exceção ao fazer a transformação xslt através de java [duplicado]
Esta pergunta é uma duplicata exata de:
recebendo erro na transformação xslt através de java 1 respostaEu tenho a classe java abaixo na qual eu estou usando o xstream rite agora, como você pode ver que na classe java abaixo eu estou gerando xml a partir do objeto
InvoiceReferenceNotificationMessage invoiceReferenceNotificationMessage = new InvoiceReferenceNotificationMessage();
invoiceReferenceNotificationMessage.setInvoiceReference("SM/829709/0315");
invoiceReferenceNotificationMessage.setABSReference("IRMAR157311");
invoiceReferenceNotificationMessage.setCurrency("GBP");
invoiceReferenceNotificationMessage.setInvoiceAmount(2546);
invoiceReferenceNotificationMessage.setPaidAmount(1245);
invoiceReferenceNotificationMessage.setBalanceAmount(0);
invoiceReferenceNotificationMessage.setValueDate(new Date());
invoiceReferenceNotificationMessage.setRemarks("abc");
InvoiceReferenceNotificationMessage invoiceReferenceNotificationMessage1 = new InvoiceReferenceNotificationMessage();
invoiceReferenceNotificationMessage1.setInvoiceReference("SM/15");
invoiceReferenceNotificationMessage1.setABSReference("I157311");
invoiceReferenceNotificationMessage1.setCurrency("EUR");
invoiceReferenceNotificationMessage1.setInvoiceAmount(255546);
invoiceReferenceNotificationMessage1.setPaidAmount(125545);
invoiceReferenceNotificationMessage1.setBalanceAmount(0);
invoiceReferenceNotificationMessage1.setValueDate(new Date());
invoiceReferenceNotificationMessage1.setRemarks("abERRc");
Mail m = new Mail();
String xslFilePath1 = "C:\\xsl\\rok.xsl";
m.setInvoiceReferenceNotificationMessage(invoiceReferenceNotificationMessage);
XStream xstream = new XStream();
xstream.alias("arokermail",Mail.class);
String abc = xstream.toXML(m);
m.setInvoiceReferenceNotificationMessage(invoiceReferenceNotificationMessage1);
xstream.alias("arokermail",Mail.class);
String def = xstream.toXML(m);
String t =abc+def;
portanto, o código acima gera o seguinte xml
<arokermail>
<invoiceReferenceNotificationMessage>
<InvoiceReference>SM/829709/0315</InvoiceReference>
<ABSReference>IRMAR157311</ABSReference>
<Currency>GBP</Currency>
<InvoiceAmount>2546.0</InvoiceAmount>
<PaidAmount>1245.0</PaidAmount>
<BalanceAmount>0.0</BalanceAmount>
<ValueDate>2015-05-22 15:44:14.741 IST</ValueDate>
<Remarks>abc</Remarks>
</invoiceReferenceNotificationMessage>
</arokermail><arokermail>
<invoiceReferenceNotificationMessage>
<InvoiceReference>SM/15</InvoiceReference>
<ABSReference>I157311</ABSReference>
<Currency>EUR</Currency>
<InvoiceAmount>255546.0</InvoiceAmount>
<PaidAmount>125545.0</PaidAmount>
<BalanceAmount>0.0</BalanceAmount>
<ValueDate>2015-05-22 15:44:14.741 IST</ValueDate>
<Remarks>abERRc</Remarks>
</invoiceReferenceNotificationMessage>
</arokermail>
agora eu também criei um xsl que eu armazenei no meu computador chamado rok.xsl, que eu quero aplicar no xml gerado como parte da transformação xsl, para que o xsl abaixo eu tenha armazenado em uma variável como mostrado abaixo
String xslFilePath1 = "C:\\xsl\\rok.xsl";
Agora, por favor, informe como aplicar esse xsl no xml gerado. O xml gerado é armazenado em uma variável de string denominada t;
String t =abc+def;
abaixo é o que eu tentei chamando uma função e passando parâmetros
String t =abc+def; //generated xml
String xslFilePath1 = "C:\\xsl\\rok.xsl";";
String outputhtml =null;
try
{
st.transform(t, xslFilePath1, outputhtml);
}
catch (TransformerConfigurationException e)
{
System.err.println("TransformerConfigurationException");
System.err.println(e);
}
catch (TransformerException e)
{
System.err.println("TransformerException");
System.err.println(e);
}
e a função que está sendo chamada é mostrada abaixo
public void transform(String dataXML, String inputXSL, String outputHTML)
throws TransformerConfigurationException, TransformerException
{
TransformerFactory factory = TransformerFactory.newInstance();
StreamSource xslStream = new StreamSource(inputXSL);
Transformer transformer = factory.newTransformer(xslStream);
StreamSource in = new StreamSource(dataXML);
StreamResult out = new StreamResult(outputHTML);
transformer.transform(in, out);
System.out.println("The generated HTML file is:" + outputHTML);
}
the error that i am getting is ..
TransformerException
javax.xml.transform.TransformerException: Result object passed to ''{0}'' is invalid.
Eu atualizei o xsl para que meu rok.xsl seja como mostrado abaixo ..
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
Hello,
<br>
</br>
<br>
</br>
Please be advised of the following payment details
<font color="black" face="Arial" size="2" >
<br>
<br>
<table border="1" cellpadding="3" cellspacing="0">
<tr bgcolor="lightblue">
<td nowrap="nowrap">Invoice Reference</td>
<td nowrap="nowrap">ABSReference</td>
<td nowrap="nowrap">Currency</td>
<td nowrap="nowrap">Invoice Amount</td>
<td nowrap="nowrap">Paid Amount</td>
<td nowrap="nowrap">Balance Amount</td>
<td nowrap="nowrap">Value Date</td>
<td nowrap="nowrap">Remarks</td>
</tr>
<xsl:for-each select="arokermail/invoiceReferenceNotificationMessage">
<tr>
<td nowrap="nowrap"><xsl:value-of select="InvoiceReference" /></td>
<td nowrap="nowrap"><xsl:value-of select="ABSReference" /></td>
<td nowrap="nowrap"><xsl:value-of select="Currency" /></td>
<td nowrap="nowrap"><xsl:value-of select="InvoiceAmount" /></td>
<td nowrap="nowrap"><xsl:value-of select="PaidAmount" /></td>
<td nowrap="nowrap"><xsl:value-of select="BalanceAmount" /></td>
<td nowrap="nowrap"><xsl:value-of select="ValueDate" /></td>
<td nowrap="nowrap"><xsl:value-of select="Remarks" /></td>
</tr>
</xsl:for-each>
<TR>
</TR>
</table>
</br>
</br>
<p>
-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
</br>
</br>
</p>
</font>
</body>
</html>
</xsl:template>
</xsl:stylesheet>