Al usar r2c y c2r FFTW en Fortran, ¿son iguales las dimensiones hacia adelante y hacia atrás?
Blow es un archivo principal
PROGRAM SPHEROID
USE nrtype
USE SUB_INFO
INCLUDE "/usr/local/include/fftw3.f"
INTEGER(I8B) :: plan_forward, plan_backward
INTEGER(I4B) :: i, t, int_N
REAL(DP) :: cth_i, sth_i, real_i, perturbation
REAL(DP) :: PolarEffect, dummy, x1, x2, x3
REAL(DP), DIMENSION(4096) :: dummy1, dummy2, gam, th, ph
REAL(DP), DIMENSION(4096) :: k1, k2, k3, k4, l1, l2, l3, l4, f_in
COMPLEX(DPC), DIMENSION(2049) :: output1, output2, f_out
CHARACTER(1024) :: baseOutputFilename
CHARACTER(1024) :: outputFile, format_string
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
int_N = 4096
! File Open Section
format_string = '(I5.5)'
! Write the coodinates at t = 0
do i = 1, N
real_i = real(i)
gam(i) = 2d0*pi/real_N
perturbation = 0.01d0*dsin(2d0*pi*real_i/real_N)
ph(i) = 2d0*pi*real_i/real_N + perturbation
th(i) = pi/3d0 + perturbation
end do
! Initialization Section for FFTW PLANS
call dfftw_plan_dft_r2c_1d(plan_forward, int_N, f_in, f_out, FFTW_ESTIMATE)
call dfftw_plan_dft_c2r_1d(plan_backward, int_N, f_out, f_in, FFTW_ESTIMATE)
! Runge-Kutta 4th Order Method Section
do t = 1, Iter_N
call integration(th, ph, gam, k1, l1)
do i = 1, N
dummy1(i) = th(i) + 0.5d0*dt*k1(i)
end do
do i = 1, N
dummy2(i) = ph(i) + 0.5d0*dt*l1(i)
end do
call integration(dummy1, dummy2, gam, k2, l2)
do i = 1, N
dummy1(i) = th(i) + 0.5d0*dt*k2(i)
end do
do i = 1, N
dummy2(i) = ph(i) + 0.5d0*dt*l2(i)
end do
call integration(dummy1, dummy2, gam, k3, l3)
do i = 1, N
dummy1(i) = th(i) + dt*k3(i)
end do
do i = 1, N
dummy2(i) = ph(i) + dt*l3(i)
end do
call integration(dummy1, dummy2, gam, k4, l4)
do i = 1, N
cth_i = dcos(th(i))
sth_i = dsin(th(i))
PolarEffect = (nv-sv)*dsqrt(1d0+a*sth_i**2) + (nv+sv)*cth_i
PolarEffect = PolarEffect/(sth_i**2)
th(i) = th(i) + dt*(k1(i) + 2d0*k2(i) + 2d0*k3(i) + k4(i))/6d0
ph(i) = ph(i) + dt*(l1(i) + 2d0*l2(i) + 2d0*l3(i) + l4(i))/6d0
ph(i) = ph(i) + dt*0.25d0*PolarEffect/pi
end do
!! Fourier Filtering Section
call dfftw_execute_dft_r2c(plan_forward, th, output1)
do i = 1, N/2+1
dummy = abs(output1(i))
if (dummy.lt.threshhold) then
output1(i) = dcmplx(0.0d0)
end if
end do
call dfftw_execute_dft_c2r(plan_backward, output1, th)
do i = 1, N
th(i) = th(i)/real_N
end do
call dfftw_execute_dft_r2c(plan_forward, ph, output2)
do i = 1, N/2+1
dummy = abs(output2(i))
if (dummy.lt.threshhold) then
output2(i) = dcmplx(0.0d0)
end if
end do
call dfftw_execute_dft_c2r(plan_backward, output2, ph)
do i = 1, N
ph(i) = ph(i)/real_N
end do
!! Data Writing Section
write(baseOutputFilename, format_string) t
outputFile = "xyz" // baseOutputFilename
open(unit=7, file=outputFile)
outputFile = "Fsptrm" // baseOutputFilename
open(unit=8, file=outputFile)
do i = 1, N
x1 = dsin(th(i))*dcos(ph(i))
x2 = dsin(th(i))*dsin(ph(i))
x3 = dsqrt(1d0+a)*dcos(th(i))
write(7,*) x1, x2, x3
end do
do i = 1, N/2+1
write(8,*) abs(output1(i)), abs(output2(i))
end do
close(7)
close(8)
do i = 1, N/2+1
output1(i) = dcmplx(0.0d0)
end do
do i = 1, N/2+1
output2(i) = dcmplx(0.0d0)
end do
end do
! Destroying Process for FFTW PLANS
call dfftw_destroy_plan(plan_forward)
call dfftw_destroy_plan(plan_backward)
END PROGRAM
A continuación se muestra un archivo de subrutina para integración
! We implemented Shelly's spectrally accurate convergence method
SUBROUTINE integration(in1,in2,in3,out1,out2)
USE nrtype
USE SUB_INFO
INTEGER(I4B) :: i, j
REAL(DP) :: th_i, th_j, gi, ph_i, ph_j, gam_j, v1, v2
REAL(DP), DIMENSION(N), INTENT(INOUT) :: in1, in2, in3, out1, out2
REAL(DP) :: ui, uj, part1, part2, gj, cph, sph
REAL(DP) :: denom, numer, temp
do i = 1, N
out1(i) = 0d0
end do
do i = 1, N
out2(i) = 0d0
end do
do i = 1, N
th_i = in1(i)
ph_i = in2(i)
ui = dcos(th_i)
part1 = dsqrt(1d0+a)/(dsqrt(-a)*ui+dsqrt(1d0+a-a*ui*ui))
part1 = part1**(dsqrt(-a))
part2 = (dsqrt(1d0+a-a*ui*ui)+ui)/(dsqrt(1d0+a-a*ui*ui)-ui)
part2 = dsqrt(part2)
gi = dsqrt(1d0-ui*ui)*part1*part2
do j = 1, N
if (mod(i+j,2).eq.1) then
th_j = in1(j)
ph_j = in2(j)
gam_j = in3(j)
uj = dcos(th_j)
part1 = dsqrt(1d0+a)/(dsqrt(-a)*uj+dsqrt(1d0+a-a*uj*uj))
part1 = part1**(dsqrt(-a))
part2 = (dsqrt(1d0+a-a*uj*uj)+uj)/(dsqrt(1d0+a-a*uj*uj)-uj)
part2 = dsqrt(part2)
gj = dsqrt(1d0-ui*ui)*part1*part2
cph = dcos(ph_i-ph_j)
sph = dsin(ph_i-ph_j)
numer = dsqrt(1d0-uj*uj)*sph
denom = (gj/gi*(1d0-ui*ui) + gi/gj*(1d0-uj*uj))*0.5d0
denom = denom - dsqrt((1d0-ui*ui)*(1d0-uj*uj))*cph
denom = denom + krasny_delta
v1 = -0.25d0*gam_j*numer/denom/pi
temp = dsqrt(1d0+(1d0-ui*ui)*a)
numer = -(gj/gi)*(temp+ui)
numer = numer + (gi/gj)*((1d0-uj*uj)/(1d0-ui*ui))*(temp-ui)
numer = numer + 2d0*ui*dsqrt((1d0-uj*uj)/(1d0-ui*ui))*cph
numer = 0.5d0*numer
v2 = -0.25d0*gam_j*numer/denom/pi
out1(i) = out1(i) + 2d0*v1
out2(i) = out2(i) + 2d0*v2
end if
end do
end do
END
Debajo hay un archivo de módulo
module nrtype
Implicit none
!integer
INTEGER, PARAMETER :: I8B = SELECTED_INT_KIND(20)
INTEGER, PARAMETER :: I4B = SELECTED_INT_KIND(9)
INTEGER, PARAMETER :: I2B = SELECTED_INT_KIND(4)
INTEGER, PARAMETER :: I1B = SELECTED_INT_KIND(2)
!real
INTEGER, PARAMETER :: SP = KIND(1.0)
INTEGER, PARAMETER :: DP = KIND(1.0D0)
!complex
INTEGER, PARAMETER :: SPC = KIND((1.0,1.0))
INTEGER, PARAMETER :: DPC = KIND((1.0D0,1.0D0))
!defualt logical
INTEGER, PARAMETER :: LGT = KIND(.true.)
!mathematical constants
REAL(DP), PARAMETER :: pi = 3.141592653589793238462643383279502884197_dp
!derived data type s for sparse matrices,single and double precision
!User-Defined Constants
INTEGER(I4B), PARAMETER :: N = 4096, Iter_N = 20000
REAL(DP), PARAMETER :: real_N = 4096d0
REAL(DP), PARAMETER :: a = -0.1d0, dt = 0.001d0, krasny_delta = 0.01d0
REAL(DP), PARAMETER :: nv = 0d0, sv = 0d0, threshhold = 0.00000000001d0
!N : The Number of Point Vortices, Iter_N * dt = Total time, dt : Time Step
!krasny_delta : Smoothing Parameter introduced by R.Krasny
!nv : Northern Vortex Strength, sv : Southern Vortex Strength
!a : The Eccentricity in the direction of z , threshhold : Filtering Threshhold
end module nrtype
A continuación se muestra un archivo de información de subrutina
MODULE SUB_INFO
INTERFACE
SUBROUTINE integration(in1,in2,in3,out1,out2)
USE nrtype
INTEGER(I4B) :: i, j
REAL(DP) :: th_i, th_j, gi, ph_i, ph_j, gam_j, v1, v2
REAL(DP), DIMENSION(N), INTENT(INOUT) :: in1, in2, in3, out1, out2
REAL(DP) :: ui, uj, part1, part2, gj, cph, sph
REAL(DP) :: denom, numer, temp
END SUBROUTINE
END INTERFACE
END MODULE
Los compilé usando el siguiente comando
gfortran -o p0 -fbounds-check nrtype.f90 spheroid_sub_info.f90 spheroid_sub_integration.f90 spheroid_main.f90 -lfftw3 -lm -Wall -pedantic -pg
nohup ./p0 &
Tenga en cuenta que 2049 = 4096/2 + 1
Al hacer plan_backward, ¿no es correcto que usemos 2049 en lugar de 4096 ya que la dimensión de salida es 2049?
Pero cuando hago eso, explota. (Volar significa error NAN)
Si uso 4096 para hacer plan_backward, todo está bien, excepto que algunos coeficientes de Fourier son anormalmente grandes, lo que no debería suceder.
Por favor, ayúdame a usar FFTW en Fortran correctamente. Este problema me ha desanimado durante mucho tiempo.