Java-Fehler - net.ucanaccess.jdbc.UcanaccessSQLException: fehlerhafte Zeichenfolge: &#39

Ich habe einen Fehler beim Abrufen meiner auf meinem Desktop gespeicherten Datenbank mit uCanaccess.

Mein Code ist unten:

package Week11Package;

import java.util.Scanner; importiere java.sql. *;

public class dbTest1

static Scanner input = new Scanner (System.in);
static String url;
static Connection aConnection;
static Statement aStatement;
static boolean gotIt = false;

public static void main(String[] args) {

    dbTest1.initialize();
}
public static void initialize() {
    //establish the DB connection.
    url = "jdbc:odbc:MS Access Database;DBQ=.//Teams.accdb";
    try {
        //load the jdbc - odbc bridge for Windows
        Class.forName("net.ucanaccess.jdbc.UcanaccessDriver");
        //create a connection instance
        aConnection = DriverManager.getConnection("jdbc:ucanaccess:///Users/Vince/Desktop/Teams.accdb");
        //create statement object instance for this connection
        aStatement = aConnection.createStatement();
        String sqlQuery = "SELECT PlayerID, PlayerName, TeamID " +
                    "FROM PLAYER"+"'";
        ResultSet rs = aStatement.executeQuery (sqlQuery);
        gotIt = rs.next();
        if (gotIt) {
            System.out.println("Connected to DB & found Data!!!");
            System.out.println("Which Player ID are you looking for?");
            String stringpID = input.next();
            boolean found = false;
            while(gotIt){
                //extract the data
                String pID = rs.getString (1);
                if (pID.equals(stringpID))
                    found = true;
                String pName = rs.getString (2);
                String tID = rs.getString (3);
                System.out.println(pID+" " +pName+ " "+tID);
                gotIt = rs.next();
            }
            if (found)
                System.out.println("The player ws found");
        }
        aStatement.close();
        aConnection.close();
    }
catch (ClassNotFoundException e) {
        System.err.println(e);
    }
    catch (SQLException e) {
        System.err.println(e);
    } 
}

}

Ich würde mich über Ratschläge zur Behebung dieses Fehlers freuen.

ielen Dank, Vin

Antworten auf die Frage(1)

Ihre Antwort auf die Frage