Ich habe diesen Code:

    import java.awt.Color;
    import java.awt.Graphics;
    import java.awt.event.KeyEvent;
    import java.awt.event.KeyListener;
    import java.awt.event.MouseEvent;
    import java.awt.event.MouseListener;

    import javax.swing.JApplet;


    public class applet extends JApplet implements KeyListener, MouseListener{
        int a = 0;
        int b = 0;
        public void init(){
            setSize(500,500);
            addKeyListener( this );
             addMouseListener( this );
        }
        public void paint(Graphics g){
            g.setColor(Color.BLUE);
            g.fillRect(a, b, 400, 400);
        }
        @Override
        public void keyPressed(KeyEvent e) {
        System.out.println("Hello!")    
switch(e.getKeyCode()){
                case KeyEvent.VK_DOWN: a -= 5;
                break;
                case KeyEvent.VK_UP: a += 5;
                break;
                case KeyEvent.VK_RIGHT: b += 5;
                break;
                case KeyEvent.VK_LEFT: b -= 5;
                break;
            }
            repaint();
        }
        @Override
        public void keyReleased(KeyEvent e) {
            // TODO Auto-generated method stub

        }
        @Override
        public void keyTyped(KeyEvent e) {
            // TODO Auto-generated method stub

        }
        @Override
        public void mouseClicked(MouseEvent arg0) {
            // TODO Auto-generated method stub

        }
        @Override
        public void mouseEntered(MouseEvent arg0) {
            // TODO Auto-generated method stub

        }
        @Override
        public void mouseExited(MouseEvent arg0) {
            // TODO Auto-generated method stub

        }
        @Override
        public void mousePressed(MouseEvent arg0) {
            // TODO Auto-generated method stub

        }
        @Override
        public void mouseReleased(MouseEvent arg0) {
            // TODO Auto-generated method stub

        }
    }

und es erreicht nicht einmal die switch-Anweisung, wie aus meinem Debug-Println-Code hervorgeht. Warum passiert das und was kann ich tun, um das zu beheben? Bitte hasse es nicht, wenn dies zu umfassend ist, da ich ein absoluter Neuling in diesem Thema bin