я знаком с многопоточностью и яМы успешно разработали много многопоточных программ на Java и Objective-C. Но я не могt достичь следующего в C, используя pthreads без использования соединения из основного потока:

#include 
#include 
#include 

#define NUM_OF_THREADS 2

struct thread_data {
    int start;
    int end;
    int *arr;
};

void print(int *ints, int n);
void *processArray(void *args);

int main(int argc, const char * argv[])
{
    int numOfInts = 10;
    int *ints = malloc(numOfInts * sizeof(int));
    for (int i = 0; i < numOfInts; i++) {
        ints[i] = i;
    }
    print(ints, numOfInts); // prints [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

    pthread_t threads[NUM_OF_THREADS];
    struct thread_data thread_data[NUM_OF_THREADS];

    // these vars are used to calculate the index ranges for each thread
    int remainingWork = numOfInts, amountOfWork;
    int startRange, endRange = -1;

    for (int i = 0; i < NUM_OF_THREADS; i++) {

        amountOfWork = remainingWork / (NUM_OF_THREADS - i);
        startRange = endRange + 1;
        endRange   = startRange + amountOfWork - 1;

        thread_data[i].arr   = ints;
        thread_data[i].start = startRange;
        thread_data[i].end   = endRange;

        pthread_create(&threads[i], NULL, processArray, (void *)&thread_data[i]);

        remainingWork -= amountOfWork;      
    }

    // 1. Signal to the threads to start working


    // 2. Wait for them to finish


    print(ints, numOfInts); // should print [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

    free(ints);
    return 0;
}

void *processArray(void *args)
{
    struct thread_data *data = (struct thread_data *)args;
    int *arr  = data->arr;
    int start = data->start;
    int end   = data->end;

    // 1. Wait for a signal to start from the main thread


    for (int i = start; i end;

     // Do the work
     for (int i = start; i