Стол :

    CREATE TABLE GUESTS (
      GUEST_ID int IDENTITY(1,1) PRIMARY KEY, 
      GUEST_NAME VARCHAR(50), 
      GUEST_SURNAME VARCHAR(50), 
      ADRESS VARCHAR(100), 
      CITY VARCHAR(50), 
      CITY_CODE VARCHAR(10), 
      COUNTRY VARCHAR(50), 
      STATUS VARCHAR(20), 
      COMMENT nvarchar(max);

Для ведения журнала:

CREATE TABLE AUDIT_GUESTS (
  ID int IDENTITY(1,1) PRIMARY KEY, 
  GUEST_ID int,
  OLD_GUEST_NAME VARCHAR(50), 
  NEW_GUEST_NAME VARCHAR(50), 
  OLD_GUEST_SURNAME VARCHAR(50), 
  NEW_GUEST_SURNAME VARCHAR(50),
  OLD_ADRESS VARCHAR(100), 
  NEW_ADRESS VARCHAR(100),
  OLD_CITY VARCHAR(50), 
  NEW_CITY VARCHAR(50),
  OLD_CITY_CODE VARCHAR(10), 
  NEW_CITY_CODE VARCHAR(10), 
  OLD_COUNTRY VARCHAR(50), 
  NEW_COUNTRY VARCHAR(50), 
  OLD_STATUS VARCHAR(20), 
  NEW_STATUS VARCHAR(20), 
  OLD_COMMENT nvarchar(max), 
  NEW_COMMENT nvarchar(max), 
  AUDIT_ACTION varchar(100),
  AUDIT_TIMESTAMP datetime);

Я хотел бы создать триггер на моемGUESTS таблица для регистрации всех изменений в моемAUDIT_GUESTS Таблица. Как я могу сделать это в SQL Server 2014 Express?

Я старался :

create TRIGGER trgAfterUpdate ON [dbo].[GUESTS] 
FOR UPDATE
AS
    declare @GUEST_ID int;
    declare @GUEST_NAME varchar(50);
    declare @GUEST_SURNAME VARCHAR(50);
    declare @ADRESS VARCHAR(100); 
    declare @CITY VARCHAR(50);
    declare @CITY_CODE VARCHAR(10); 
    declare @COUNTRY VARCHAR(50);
    declare @STATUS VARCHAR(20);
    declare @COMMENT nvarchar(max);
    declare @AUDIT_ACTION varchar(100);
    declare @AUDIT_TIMESTAMP datetime;

    select @GUEST_ID=i.GUEST_ID from inserted i;            
    select @GUEST_NAME=i.GUEST_NAME from inserted i;    
    select @GUEST_SURNAME=i.GUEST_SURNAME from inserted i;
    select @ADRESS=i.ADRESS from inserted i;
    select @CITY=i.CITY from inserted i;
    select @CITY_CODE=i.CITY_CODE from inserted i;
    select @COUNTRY=i.COUNTRY from inserted i;
    select @STATUS=i.STATUS from inserted i;
    select @COMMENT=i.COMMENT from inserted i;

        if update(GUEST_NAME)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(GUEST_SURNAME)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(ADRESS)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(CITY)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(CITY_CODE)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(COUNTRY)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(STATUS)
        set @audit_action='Updated Record -- After Update Trigger.';

        if update(COMMENT)
        set @audit_action='Updated Record -- After Update Trigger.';

        insert into AUDIT_GUESTS
           (GUEST_ID,GUEST_NAME,GUEST_SURNAME,ADRESS,CITY,CITY_CODE,COUNTRY,STATUS,COMMENT,audit_action,AUDIT_TIMESTAMP) 
    values(@GUEST_ID,@GUEST_NAME,@GUEST_SURNAME,@ADRESS,@CITY,@CITY_CODE,@COUNTRY,@STATUS,@COMMENT,@audit_action,getdate());
    GO

Работает вроде нормально, но я бы хотел увидеть старые новые значения.

В SQLite у меня было:

CREATE TRIGGER [LOG_UPDATE]
AFTER UPDATE OF [GUEST_NAME], [GUEST_SURNAME], [ADRESS], [CITY], [CITY_CODE], [COUNTRY], [STATUS], [COMMENT]
ON [GUESTS]
BEGIN
INSERT INTO GUESTS_LOG
 ( GUEST_ID,
   NAME_OLD,NAME_NEW,
   SURNAME_OLD,SURNAME_NEW,
   ADRESS_OLD,ADRESS_NEW,
   CITY_OLD,CITY_NEW,
   CITY_CODE_OLD,CITY_CODE_NEW,
   COUNTRY_OLD,COUNTRY_NEW,
   STATUS_OLD,STATUS_NEW,   
   COMMENT_OLD,COMMENT_NEW,sqlAction,DATE_TIME)   

   VALUES   

 (OLD.GUEST_ID,
  OLD.GUEST_NAME,NEW.GUEST_NAME, 
  OLD.GUEST_SURNAME,NEW.GUEST_SURNAME,
  OLD.ADRESS,NEW.ADRESS,
  OLD.CITY,NEW.CITY,
  OLD.CITY_CODE,NEW.CITY_CODE,
  OLD.COUNTRY,NEW.COUNTRY,  
  OLD.STATUS,NEW.STATUS,
  OLD.COMMENT,NEW.COMMENT,'record changed',datetime('now','localtime'));  

END

и это работало хорошо. Просто не знаю, как передать это на сервер SQL. Только начал изучать это.