Почему мой параллельный код генерирует ошибку?
Вопрос 1: Когдаsys.stdout.write
не оборачивается в отдельную функцию, код ниже не работает.
Вопрос 2: Когдаssys.stdout.write
обернут в отдельную функцию, код печатает пробелы между каждой буквой.
Код (v1):
#!/usr/bin/env python
import pp
import sys
def main():
server = pp.Server()
for c in "Hello World!\n":
server.submit(sys.stdout.write, (c,), (), ("sys",))()
if __name__=="__main__":
main()
Трассировка:
$ ./parhello.py
Traceback (most recent call last):
File "./parhello.py", line 15, in
main()
File "./parhello.py", line 12, in main
server.submit(write, (c,), (), ("sys",))()
File "/Library/Python/2.7/site-packages/pp.py", line 461, in submit
sfunc = self.__dumpsfunc((func, ) + depfuncs, modules)
File "/Library/Python/2.7/site-packages/pp.py", line 639, in __dumpsfunc
sources = [self.__get_source(func) for func in funcs]
File "/Library/Python/2.7/site-packages/pp.py", line 706, in __get_source
sourcelines = inspect.getsourcelines(func)[0]
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 688, in getsourcelines
lines, lnum = findsource(object)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 527, in findsource
file = getsourcefile(object)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 446, in getsourcefile
filename = getfile(object)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/inspect.py", line 422, in getfile
'function, traceback, frame, or code object'.format(object))
TypeError: is not a module, class, method, function, traceback, frame, or code object
make: *** [test] Error 1
Код (v2):
#!/usr/bin/env python
import pp
import sys
def hello(c):
sys.stdout.write(c)
def main():
server = pp.Server()
for c in "Hello World!\n":
server.submit(hello, (c,), (), ("sys",))()
if __name__=="__main__":
main()
Трассировка:
$ ./parhello.py
H e l l o W o r l d !