как сделать jmeter для выбора уникальных значений из ответа для каждой итерации

У меня есть следующий ответ от JMeter:

{"tot_cnt":{"tc":"41651","rpp":"100","pdid":"1594"},"mg":[{"id":"683","rsd":"6-May-13 \/ 6-May-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/txq8xa56","inv":null,"rbp":"0","pdid":"106","di":"0","pl":"0","spl":null},{"id":"17670","rsd":"6-Jun-13 \/ 6-Jun-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/ckwu5qe8","inv":null,"rbp":"0","pdid":"106","di":"0","pl":"0","spl":null},{"id":"22","rsd":"22-Jul-13 \/ 22-Jul-13","col":"black","cc":"c_1884","pn":"old_THE ORTHODONTIC CLINC","loc":"15 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"15","cid":"1992","iq":"0","wid":"WI\/tldj53ky","inv":null,"rbp":"0","pdid":"1582","di":"0","pl":"0","spl":null},{"id":"686","rsd":"29-Jul-13 \/ 29-Jul-13","col":"black","cc":"c_197","pn":"old_NEXUS MARKETING CAMPAIGNS-PERMANENT","loc":"PTD - 07 \/ 18 \/ BX","isf":"1","isl":"0","tq":"180","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/n4olde1g","inv":null,"rbp":"0","pdid":"107","di":"0","pl":"0","spl":null},{"id":"73","rsd":"5-Aug-13 \/ 5-Aug-13","col":"black","cc":"c_2357","pn":"old_KCA DEATAG","loc":"338 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"338","cid":"1914","iq":"0","wid":"WI\/zdqbx1zx","inv":null,"rbp":"0","pdid":"1578","di":"0","pl":"0","spl":null},{"id":"137","rsd":"5-Aug-13 \/ 5-Aug-13","col":"black","cc":"c_1219","pn":"old_TYPHOO - J01-TYPHOO- JULY 2013","loc":"56 - 24 \/ 81 \/ L3","isf":"1","isl":"0","tq":"2","pi":"0","st":"2","dsid":"56","cid":"2090","iq":"0","wid":"WI\/azdtc77c","inv":null,"rbp":"0","pdid":"1086","di":"0","pl":"0","spl":null},{"id":"70","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2394","pn":"old_SKF UK LTD","loc":"338 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"338","cid":"1914","iq":"0","wid":"WI\/45uzkvp3","inv":null,"rbp":"0","pdid":"1556","di":"0","pl":"0","spl":null},{"id":"1253","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2349","pn":"old_JUST TILES","loc":"PTD - 34 \/ 0M \/ MR","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"528","cid":"1955","iq":"0","wid":"WI\/ofunwm5s","inv":null,"rbp":"0","pdid":"1559","di":"0","pl":"0","spl":null},{"id":"1320","rsd":"12-Aug-13 \/ 12-Aug-13","col":"black","cc":"c_2073","pn":"old_NEW COLLEGE SWINDON SUMMER CAMPAIGN","loc":"PTD - 34 \/ 0N \/ RS","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"528","cid":"1955","iq":"0","wid":"WI\/gpp1dejn","inv":null,"rbp":"0","pdid":null,"di":"0","pl":"0","spl":null},{"id":"27","rsd":"19-Aug-13 \/ 19-Aug-13","col":"black","cc":"c_2138","pn":"old_WIRED STUDIO PEAK MEGA REAR","loc":"15 - 34 \/ 0N \/ RS","isf":"1","isl":"1","tq":"1","pi":"0","st":"2","dsid":"15","cid":"1992","iq":"0","wid":"WI\/b5m0iyuc","inv":null,"rbp":"0","pdid":"1597","di":"0","pl":"0","spl":null},{"id":"561","rsd":"19-Aug-13 \/ 19-Aug-13","col":"black","cc":"c_3737","pn":"old_LONDON ROAD BRIDGE SCHEME DERBY CITY COUNCIL","loc":"PTD - 83 \/ 4I \/ WB","isf":"1","isl":"0","tq":"1","pi":"0","st":"2","dsid":"527","cid":"1917","iq":"0","wid":"WI\/1s1xaqxw","inv":null,"rbp":"0","pdid":"2574","di":"0","pl":"0","spl":null}

я использовал(?=(?:(?!isf).)*?isf":"1)(?=(?:(?!isl).)*?isl":"0)(?=(?:(?!st).)*?st":"2)"id":"(\d+) регулярное выражение для выбора необходимого идентификатора.

Когда я запускаю тест с 5 пользователями, во время нескольких тестов один и тот же идентификатор выбирается для разных итераций, что приводит к ошибке.

Мне нужно, чтобы jmeter извлекал некоторые уникальные значения из ответа для каждой итерации. Как я могу это сделать? Заранее спасибо.

Ответы на вопрос(1)

Ваш ответ на вопрос